Question:
A 10cm by 10 cm by 10 cm woodblock with a density of 700kg/{m}^{3} floats in water.
a.What is the distance from the top of the block to the water if the water is fresh?
b.If it’s seawater?
Answer:
(a).
The density of freshwater is ρ_water = 1000 kg/m³
ΣF = 0
– (ρ_wood)g(V_wood) + (ρ_water)g(v_wood) = 0
(v_wood)/(V_wood) = (ρ_wood)/(ρ_water)
(10 * 10 * h)/(10 * 10 * 10) = (700)/(1000)
h = 7 cm
the distance from the top of the block to the water is 10 – 7 = 3 cm
(b).
density of seawater is ρ_sea = 1030 kg/m³
(v_wood)/(V_wood) = (ρ_wood)/(ρ_sea)
(10 * 10 * h’)/(10 * 10 * 10) = (700)/(1030)
h’ = 6.79611 cm
the distance from the top of the block to the water is 10 – 6.79611 = 3.20389 cm
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What is the distance from the top of the block to the water if the water is fresh?
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