What is the distance from the top of the block to the water if the water is fresh?

What is the distance from the top of the block to the water if the water is fresh?

Question:

A 10cm by 10 cm by 10 cm woodblock with a density of 700kg/{m}^{3} floats in water.

a.What is the distance from the top of the block to the water if the water is fresh?

b.If it’s seawater?

Answer:

(a).

The density of freshwater is ρ_water = 1000 kg/m³

ΣF = 0

– (ρ_wood)g(V_wood) + (ρ_water)g(v_wood) = 0

(v_wood)/(V_wood) = (ρ_wood)/(ρ_water)

(10 * 10 * h)/(10 * 10 * 10) = (700)/(1000)

h = 7 cm

the distance from the top of the block to the water is 10 – 7 = 3 cm

(b).

density of seawater is ρ_sea = 1030 kg/m³

(v_wood)/(V_wood) = (ρ_wood)/(ρ_sea)

(10 * 10 * h’)/(10 * 10 * 10) = (700)/(1030)

h’ = 6.79611 cm

the distance from the top of the block to the water is 10 – 6.79611 = 3.20389 cm

Credit goes to Brainly

What is the distance from the top of the block to the water if the water is fresh?

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